A compound data type
So far we have seen five types: int, float,
bool, NoneType and str. Strings are
qualitatively different from the other four because they are made up of smaller
pieces---characters.
Types that comprise smaller pieces are called compound data types. Depending on what we are doing, we may want to treat a compound data type as a single thing, or we may want to access its parts. This ambiguity is useful.
The bracket operator selects a single character from a string.
>>> fruit = "banana" >>> letter = fruit[1] >>> print letter
The expression fruit[1] selects character number 1 from
fruit. The variable letter refers to the result.
When we display letter, we get a surprise:
a
The first letter of "banana" is not a. Unless you
are a computer scientist. For perverse reasons, computer scientists always
start counting from zero. The 0th letter (zero-eth
) of
"banana" is b. The 1th letter (one-eth
) is
a, and the 2th (two-eth
) letter is n.
If you want the zero-eth letter of a string, you just put 0, or any expression with the value 0, in the brackets:
>>> letter = fruit[0] >>> print letter b
The expression in brackets is called an index. An index specifies a member of an ordered set, in this case the set of characters in the string. The index indicates which one you want, hence the name. It can be any integer expression.
Length
The len function returns the number of characters in a string:
>>> fruit = "banana" >>> len(fruit) 6
To get the last letter of a string, you might be tempted to try something like this:
length = len(fruit) last = fruit[length] # ERROR!
That won't work. It causes the runtime error
IndexError: string index out of range. The reason
is that there is no 6th letter in "banana". Since we started
counting at zero, the six letters are numbered 0 to 5. To get the last
character, we have to subtract 1 from length:
length = len(fruit) last = fruit[length-1]
Alternatively, we can use negative indices, which count backward from the
end of the string. The expression fruit[-1] yields the last
letter, fruit[-2] yields the second to last, and so on.
Traversal and the for loop
A lot of computations involve processing a string one character at a time.
Often they start at the beginning, select each character in turn, do something
to it, and continue until the end. This pattern of processing is called a
traversal. One way to encode a traversal is with a
while statement:
index = 0 while index < len(fruit): letter = fruit[index] print letter index = index + 1
This loop traverses the string and displays each letter on a line by itself.
The loop condition is index < len(fruit), so when
index is equal to the length of the string, the condition is false,
and the body of the loop is not executed. The last character accessed is the
one with the index len(fruit)-1, which is the last character in
the string.
Using an index to traverse a set of values is so common that Python provides
an alternative, simpler syntax---the for loop:
for char in fruit: print char
Each time through the loop, the next character in the string is assigned
to the variable char. The loop continues until no characters are
left.
The following example shows how to use concatenation and a for
loop to generate an abecedarian series. Abecedarian
refers to a series
or list in which the elements appear in alphabetical order. For example, in
Robert McCloskey's book Make Way for Ducklings, the names of the
ducklings are Jack, Kack, Lack, Mack, Nack, Ouack, Pack, and Quack. This loop
outputs these names in order:
prefixes = "JKLMNOPQ" suffix = "ack" for letter in prefixes: print letter + suffix
The output of this program is:
Jack Kack Lack Mack Nack Oack Pack Qack
Of course, that's not quite right because Ouack
and Quack
are
misspelled. You'll fix this as an exercise below.
String slices
A segment of a string is called a slice. Selecting a slice is similar to selecting a character:
>>> s = "Peter, Paul, and Mary" >>> print s[0:5] Peter >>> print s[7:11] Paul >>> print s[17:21] Mary
The operator [n:m] returns the part of the string from the
n-eth
character to the m-eth
character, including the first but
excluding the last. This behavior is counterintuitive; it makes more sense if
you imagine the indices pointing between the characters, as in the
following diagram:

If you omit the first index (before the colon), the slice starts at the beginning of the string. If you omit the second index, the slice goes to the end of the string. Thus:
>>> fruit = "banana" >>> fruit[:3] 'ban' >>> fruit[3:] 'ana'
What do you think s[:] means?
String comparison
The comparison operators work on strings. To see if two strings are equal:
if word == "banana": print "Yes, we have no bananas!"
Other comparison operations are useful for putting words in alphabetical order:
if word < "banana": print "Your word," + word + ", comes before banana." elif word > "banana": print "Your word," + word + ", comes after banana." else: print "Yes, we have no bananas!"
You should be aware, though, that Python does not handle upper- and lowercase letters the same way that people do. All the uppercase letters come before all the lowercase letters. As a result:
Your word, Zebra, comes before banana.
A common way to address this problem is to convert strings to a standard format, such as all lowercase, before performing the comparison. A more difficult problem is making the program realize that zebras are not fruit.
Strings are immutable
It is tempting to use the [] operator on the left side of an
assignment, with the intention of changing a character in a string. For
example:
greeting = "Hello, world!" greeting[0] = 'J' # ERROR! print greeting
Instead of producing the output Jello, world!, this code
produces the runtime error
TypeError: 'str' object doesn't support item assignment.
Strings are immutable, which means you can't change an existing string. The best you can do is create a new string that is a variation on the original:
greeting = "Hello, world!" newGreeting = 'J' + greeting[1:] print newGreeting
The solution here is to concatenate a new first letter onto a slice of
greeting. This operation has no effect on the original string.
A find function
What does the following function do?
def find(strng, ch): index = 0 while index < len(strng): if strng[index] == ch: return index index = index + 1 return -1
In a sense, find is the opposite of the []
operator. Instead of taking an index and extracting the corresponding
character, it takes a character and finds the index where that character
appears. If the character is not found, the function returns
-1.
This is the first example we have seen of a return statement
inside a loop. If strng[index] == ch, the function returns
immediately, breaking out of the loop prematurely.
If the character doesn't appear in the string, then the program exits the
loop normally and returns -1.
This pattern of computation is sometimes called a eureka
traversal
because as soon as we find what we are looking for, we can cry Eureka!
and stop looking.
Looping and counting
The following program counts the number of times the letter a
appears in a string:
fruit = "banana" count = 0 for char in fruit: if char == 'a': count = count + 1 print count
This program demonstrates another pattern of computation called a
counter. The variable count is initialized to 0
and then incremented each time an a is found.
(To increment is to increase by one; it is the opposite of
decrement, and unrelated to excrement,
which is a noun.)
When the loop exits, count contains the result---the total number
of a's.
The string module
The string module contains useful functions that manipulate
strings. As usual, we have to import the module before we can use it:
>>> import string
The string module includes a function named find
that does the same thing as the function we wrote. To call it we have to
specify the name of the module and the name of the function using dot notation.
>>> fruit = "banana" >>> index = string.find(fruit, "a") >>> print index 1
This example demonstrates one of the benefits of modules---they help
avoid collisions between the names of built-in functions and user-defined
functions. By using dot notation we can specify which version of
find we want.
Actually, string.find is more general than our version. First,
it can find substrings, not just characters:
>>> string.find("banana", "na")
2
Also, it takes an additional argument that specifies the index it should start at:
>>> string.find("banana", "na", 3)
4
Or it can take two additional arguments that specify a range of indices:
>>> string.find("bob", "b", 1, 2)
-1
In this example, the search fails because the letter b does not
appear in the index range from 1 to 2 (not including
2).
Character classification
It is often helpful to examine a character and test whether it is upper- or
lowercase, or whether it is a character or a digit. The string
module provides several constants that are useful for these purposes.
The string string.lowercase contains all of the letters that
the system considers to be lowercase. Similarly, string.uppercase
contains all of the uppercase letters. Try the following and see what you get:
>>> print string.lowercase >>> print string.uppercase >>> print string.digits
We can use these constants and find to classify characters. For
example, if find(lowercase, ch) returns a value other than
-1, then ch must be lowercase:
def isLower(ch): return string.find(string.lowercase, ch) != -1
Alternatively, we can take advantage of the in operator, which
determines whether a character appears in a string:
def isLower(ch): return ch in string.lowercase
As yet another alternative, we can use the comparison operator:
def isLower(ch): return 'a' <= ch <= 'z'
If ch is between a and z, it must be a
lowercase letter.
Another constant defined in the string module may surprise you
when you print it:
>>> print string.whitespace
Whitespace characters move the cursor without printing
anything. They create the white space between visible characters (at least on
white paper). The constant string.whitespace contains all the
whitespace characters, including space, tab (\t), and newline (\n).
There are other useful functions in the string module, but this
book isn't intended to be a reference manual. On the other hand, the
Python Library Reference is. Along with a wealth of other
documentation, it's available from the Python website,
http://www.python.org.
Glossary
- compound data type:
- A data type in which the values are made up of components, or elements, that are themselves values.
- traverse:
- To iterate through the elements of a set, performing a similar operation on each.
- index:
- A variable or value used to select a member of an ordered set, such as a character from a string.
- slice:
- A part of a string specified by a range of indices.
- mutable:
- A compound data types whose elements can be assigned new values.
- counter:
- A variable used to count something, usually initialized to zero and then incremented.
- increment:
- To increase the value of a variable by one.
- decrement:
- To decrease the value of a variable by one.
- whitespace:
- Any of the characters that move the cursor without printing visible
characters. The constant
string.whitespacecontains all the white-space characters.
Exercises
- Write a function that takes a string as an argument and outputs the letters backward, one per line.
- Modify:
prefixes = "JKLMNOPQ" suffix = "ack" for letter in prefixes: print letter + suffix
so thatOuackandQuackare spelled correctly. - Modify the
findfunction so that it takes a third parameter, the index in the string where it should start looking. - Encapsulate
fruit = "banana" count = 0 for char in fruit: if char == 'a': count = count + 1 print count
in a function namedcountLetters, and generalize it so that it accepts the string and the letter as arguments. - Now rewrite the
countLettersfunction so that instead of traversing the string, it uses your three-parameter version offind. - Which version of
isLowerdo you think will be fastest? Can you think of other reasons besides speed to prefer one version or the other?